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Day 29 · Cheat Sheet

Final Cheat Sheet

Every formula, rule, and theorem for AP Calculus AB in one place. Read it through the night before; do not try to learn anything new from it.


Limits & Continuity (Day 4)Forgot it? Go back and study again →

A limit exists
lim⁡x→cf(x)=L\lim_{x \to c} f(x) = L iff lim⁡x→c−f(x)=lim⁡x→c+f(x)=L\lim_{x \to c^-} f(x) = \lim_{x \to c^+} f(x) = L
Continuity at x = c
f(c)f(c) defined, lim⁡x→cf(x)\lim_{x \to c} f(x) exists, and lim⁡x→cf(x)=f(c)\lim_{x \to c} f(x) = f(c)
Limits at infinity (rational)
Compare degrees: top << bottom ⇒0\Rightarrow 0; equal ⇒\Rightarrow ratio of leading coefficients; top >> bottom ⇒±∞\Rightarrow \pm\infty
Special trig limits
lim⁡x→0sin⁡xx=1,lim⁡x→01−cos⁡xx=0\lim_{x \to 0} \dfrac{\sin x}{x} = 1, \qquad \lim_{x \to 0} \dfrac{1 - \cos x}{x} = 0
L'Hopital's Rule
If lim⁡fg\lim \dfrac{f}{g} is 00\dfrac{0}{0} or ∞∞\dfrac{\infty}{\infty}, then lim⁡fg=lim⁡f′g′\lim \dfrac{f}{g} = \lim \dfrac{f'}{g'}

Derivative Rules (Day 8)Forgot it? Go back and study again →

Definition
f′(a)=lim⁡h→0f(a+h)−f(a)hf'(a) = \lim_{h \to 0} \dfrac{f(a + h) - f(a)}{h}
Power, product, quotient
(xn)′=nxn−1,(fg)′=f′g+fg′,(fg)′=f′g−fg′g2(x^n)' = nx^{n-1}, \quad (fg)' = f'g + fg', \quad \left(\dfrac{f}{g}\right)' = \dfrac{f'g - fg'}{g^2}
Chain rule
ddxf(g(x))=f′(g(x))⋅g′(x)\dfrac{d}{dx} f(g(x)) = f'(g(x)) \cdot g'(x)
Trig
(sin⁡x)′=cos⁡x, (cos⁡x)′=−sin⁡x, (tan⁡x)′=sec⁡2x(\sin x)' = \cos x, \ (\cos x)' = -\sin x, \ (\tan x)' = \sec^2 x
(cot⁡x)′=−csc⁡2x, (sec⁡x)′=sec⁡xtan⁡x, (csc⁡x)′=−csc⁡xcot⁡x(\cot x)' = -\csc^2 x, \ (\sec x)' = \sec x \tan x, \ (\csc x)' = -\csc x \cot x
Exponential & log
(ex)′=ex,(ax)′=axln⁡a,(ln⁡x)′=1x,(log⁡ax)′=1xln⁡a(e^x)' = e^x, \quad (a^x)' = a^x \ln a, \quad (\ln x)' = \dfrac{1}{x}, \quad (\log_a x)' = \dfrac{1}{x \ln a}
Inverse trig
(sin⁡−1x)′=11−x2,(tan⁡−1x)′=11+x2,(sec⁡−1x)′=1∣x∣x2−1(\sin^{-1} x)' = \dfrac{1}{\sqrt{1 - x^2}}, \quad (\tan^{-1} x)' = \dfrac{1}{1 + x^2}, \quad (\sec^{-1} x)' = \dfrac{1}{|x|\sqrt{x^2 - 1}}
Inverse function
(f−1)′(b)=1f′(f−1(b))(f^{-1})'(b) = \dfrac{1}{f'(f^{-1}(b))}Find the input aa with f(a)=bf(a) = b first, then take 1/f′(a)1/f'(a).

Applications of the Derivative (Day 16)Forgot it? Go back and study again →

Tangent / normal line
Tangent: y=f(a)+f′(a)(x−a)y = f(a) + f'(a)(x - a); normal slope =−1f′(a)= -\dfrac{1}{f'(a)}
Motion
v(t)=s′(t), a(t)=v′(t)v(t) = s'(t), \ a(t) = v'(t). Speed =∣v(t)∣= |v(t)|. Speeding up when vv and aa have the same sign.
Increasing / decreasing
ff increasing where f′>0f' > 0; decreasing where f′<0f' < 0
1st derivative test
Local max where f′f' goes +→−+ \to -; local min where f′f' goes −→+- \to +
Concavity & inflection
Concave up where f′′>0f'' > 0; concave down where f′′<0f'' < 0; inflection where f′′f'' changes sign
2nd derivative test
f′(c)=0f'(c) = 0 and f′′(c)>0⇒f''(c) > 0 \Rightarrow local min; f′′(c)<0⇒f''(c) < 0 \Rightarrow local max
Absolute extrema (closed interval)
Compare ff at every critical number in (a,b)(a, b) and at aa and bb
Related rates
Differentiate the relating equation with respect to tt; substitute known values last
Optimization
Write the quantity in one variable using a constraint, set its derivative to 00, check it is the extremum
Linear approximation
f(x)≈f(a)+f′(a)(x−a)f(x) \approx f(a) + f'(a)(x - a) near x=ax = a

Antiderivatives & the Definite Integral (Day 19)Forgot it? Go back and study again →

Power / basic
∫xn dx=xn+1n+1+C (n≠−1),∫1x dx=ln⁡∣x∣+C\displaystyle\int x^n\,dx = \dfrac{x^{n+1}}{n+1} + C\ (n \ne -1), \quad \int \dfrac{1}{x}\,dx = \ln|x| + C
Exponential / trig
∫ex dx=ex+C, ∫sin⁡x dx=−cos⁡x+C, ∫cos⁡x dx=sin⁡x+C\displaystyle\int e^x\,dx = e^x + C, \ \int \sin x\,dx = -\cos x + C, \ \int \cos x\,dx = \sin x + C
∫sec⁡2x dx=tan⁡x+C, ∫dx1+x2=tan⁡−1x+C, ∫dx1−x2=sin⁡−1x+C\displaystyle\int \sec^2 x\,dx = \tan x + C, \ \int \dfrac{dx}{1 + x^2} = \tan^{-1} x + C, \ \int \dfrac{dx}{\sqrt{1 - x^2}} = \sin^{-1} x + C
u-substitution
∫f(g(x)) g′(x) dx=∫f(u) du\displaystyle\int f(g(x))\,g'(x)\,dx = \int f(u)\,du; for a definite integral, change the limits to uu-values
FTC Part 1
∫abf(x) dx=F(b)−F(a)\displaystyle\int_a^b f(x)\,dx = F(b) - F(a) where F′=fF' = f
FTC Part 2
ddx∫au(x)f(t) dt=f(u(x))⋅u′(x)\dfrac{d}{dx}\displaystyle\int_a^{u(x)} f(t)\,dt = f(u(x)) \cdot u'(x)
Riemann sums / trapezoid
Left/right/midpoint: ∑f(xi∗)Δx\sum f(x_i^*)\Delta x. Trapezoid: Δx2[f(x0)+2f(x1)+⋯+2f(xn−1)+f(xn)]\dfrac{\Delta x}{2}\big[f(x_0) + 2f(x_1) + \cdots + 2f(x_{n-1}) + f(x_n)\big]
Integral properties
∫ab(cf±g)=c∫abf±∫abg,∫acf+∫cbf=∫abf,∫abf=−∫baf\displaystyle\int_a^b (cf \pm g) = c\int_a^b f \pm \int_a^b g, \quad \int_a^c f + \int_c^b f = \int_a^b f, \quad \int_a^b f = -\int_b^a f

Applications of the Integral (Day 23)Forgot it? Go back and study again →

Accumulation
F(b)=F(a)+∫abF′(x) dxF(b) = F(a) + \displaystyle\int_a^b F'(x)\,dx (final = initial + total change)
Displacement vs. distance
Displacement =∫abv(t) dt= \displaystyle\int_a^b v(t)\,dt; total distance =∫ab∣v(t)∣ dt= \int_a^b |v(t)|\,dt (split at v=0v = 0)
Average value
favg=1b−a∫abf(x) dxf_{\text{avg}} = \dfrac{1}{b - a}\displaystyle\int_a^b f(x)\,dx
Area between curves
∫ab(top−bottom) dx\displaystyle\int_a^b (\text{top} - \text{bottom})\,dx or ∫cd(right−left) dy\int_c^d (\text{right} - \text{left})\,dy
Volume — disk / washer
Disk: π∫R2 dx\pi\displaystyle\int R^2\,dx. Washer: π∫(R2−r2) dx\pi\int (R^2 - r^2)\,dx (square each radius first)
Volume — known cross sections
∫abA(x) dx\displaystyle\int_a^b A(x)\,dx with AA from s=top−bottoms = \text{top} - \text{bottom}: square s2s^2; semicircle π8s2\tfrac{\pi}{8}s^2; equilateral triangle 34s2\tfrac{\sqrt{3}}{4}s^2
Separable differential equation
dydx=f(x)g(y)⇒∫dyg(y)=∫f(x) dx\dfrac{dy}{dx} = f(x)g(y) \Rightarrow \displaystyle\int \dfrac{dy}{g(y)} = \int f(x)\,dx, then use the initial condition for CC
Exponential model
dydt=ky⇒y=y0ekt\dfrac{dy}{dt} = ky \Rightarrow y = y_0 e^{kt}; half-life =ln⁡2∣k∣= \dfrac{\ln 2}{|k|}

The Big Theorems (Day 24)Forgot it? Go back and study again →

Intermediate Value Theorem
ff continuous on [a,b][a, b], NN between f(a)f(a) and f(b)f(b) ⇒\Rightarrow some c∈(a,b)c \in (a, b) has f(c)=Nf(c) = N
Extreme Value Theorem
ff continuous on [a,b][a, b] ⇒\Rightarrow ff attains an absolute max and min on [a,b][a, b]
Mean Value Theorem
ff continuous on [a,b][a, b], differentiable on (a,b)(a, b) ⇒\Rightarrow some cc has f′(c)=f(b)−f(a)b−af'(c) = \dfrac{f(b) - f(a)}{b - a}
MVT for Integrals
ff continuous on [a,b][a, b] ⇒\Rightarrow some cc has f(c)=1b−a∫abf(x) dxf(c) = \dfrac{1}{b - a}\displaystyle\int_a^b f(x)\,dx
Differentiable ⟹ continuous
The converse is false: ∣x∣|x| is continuous but not differentiable at 00

Values to know cold

Unit circle sine / cosine
sin⁡:0,12,22,32,1\sin: 0, \tfrac{1}{2}, \tfrac{\sqrt{2}}{2}, \tfrac{\sqrt{3}}{2}, 1 at 0,π6,π4,π3,π20, \tfrac{\pi}{6}, \tfrac{\pi}{4}, \tfrac{\pi}{3}, \tfrac{\pi}{2}; cosine is the same list reversed
Logs
ln⁡1=0, ln⁡e=1, e0=1, ln⁡(ab)=ln⁡a+ln⁡b, ln⁡(ap)=pln⁡a\ln 1 = 0, \ \ln e = 1, \ e^0 = 1, \ \ln(ab) = \ln a + \ln b, \ \ln(a^p) = p\ln a
Pythagorean identity
sin⁡2x+cos⁡2x=1,1+tan⁡2x=sec⁡2x\sin^2 x + \cos^2 x = 1, \quad 1 + \tan^2 x = \sec^2 x
Double angle
sin⁡2x=2sin⁡xcos⁡x,cos⁡2x=1−2sin⁡2x=2cos⁡2x−1\sin 2x = 2\sin x \cos x, \quad \cos 2x = 1 - 2\sin^2 x = 2\cos^2 x - 1