The Squeeze Theorem
For functions that oscillate wildly (like $\sin(1/x)$), direct substitution and algebra don't work — instead we trap the function between two simpler ones that share the same limit.
If near , and , then .
Step-by-Step SOP
- 1
Find a Bounded Piece
Identify the oscillating factor (usually or of something) and write its natural bound. - 2
Multiply Through Carefully
Multiply the inequality by the remaining factor, watching whether it's non-negative. - 3
Evaluate Both Outer Limits
If both outer bounds converge to the same value , the squeezed function also converges to .
Practice Exercises
Example 01Medium
Evaluate .
Watch the TikTok ExplanationThe Squeeze Theorem→NEED A HINT?
Start from the bounded range of , then multiply through by .
SHOW DETAILED EXPLANATION
Step 1: Start with the Bounded Range
for all .
Step 2: Multiply by $x^2$
Since , the inequality direction stays the same: .
Step 3: Evaluate the Outer Limits
and .
Step 4: Apply the Squeeze Theorem
Since both outer limits equal 0, .
Example 02Medium
Evaluate .
NEED A HINT?
Same technique as Example 1 — start with the range of .
SHOW DETAILED EXPLANATION
Step 1: Bound the Cosine Term
for all .
Step 2: Multiply by $x^4$
, since .
Step 3: Squeeze
, so .
Example 03Medium
If for all , find .
NEED A HINT?
You're already given both bounding functions directly — you don't need to build them yourself this time.
SHOW DETAILED EXPLANATION
Step 1: Evaluate the Lower Bound's Limit
.
Step 2: Evaluate the Upper Bound's Limit
.
Step 3: Apply the Squeeze Theorem
Since both bounds converge to 1, — even without knowing a formula for itself.
Common Pitfalls
- ⚠You Cannot Just 'Plug In' and have no limit at all as (they oscillate infinitely) — the trick only works because you multiply by a term (, ) that squeezes both bounds to 0.
- ⚠Check the Inequality DirectionMultiplying an inequality by a negative quantity flips it. Always confirm the multiplier (, , etc.) is non-negative before keeping the same direction.
