-1

Day -1

Prep Graphical Intuition


Average Rate of Change (AROC) & Secant Lines

AROC measures the 'average' steepness of a function over a fixed interval. Geometrically, it represents the slope of the Secant Line—a straight line that cuts through two specific points on a curve.

Core Theorem
The AROC Formula: For a function f(x)f(x) on the interval [a,b][a, b], the average rate of change is msec=f(b)f(a)bam_{sec} = \frac{f(b) - f(a)}{b - a}.
Step-by-Step SOP
  1. 1

    Identify the Interval

    Note the start (aa) and end (bb) x-values.
  2. 2

    Map to Y-values

    Find the height of the graph at those two points.
  3. 3

    Calculate Slope

    Use Change in YChange in X\frac{\text{Change in Y}}{\text{Change in X}}.

Practice Exercises


Example 01Easy
Find the AROC of f(x)=xf(x) = \sqrt{x} on the interval [4,9][4, 9].
NEED A HINT?
Calculate the y-values for x=4x=4 and x=9x=9 first.
SHOW DETAILED EXPLANATION

Step 1: Evaluate Points

f(4)=2f(4) = 2 and f(9)=3f(9) = 3. Points are (4,2)(4, 2) and (9,3)(9, 3).

Step 2: Slope Formula

m=3294=15=0.2m = \frac{3 - 2}{9 - 4} = \frac{1}{5} = 0.2.
Example 02Medium
A cup of coffee cools from 180F180^{\circ}F to 100F100^{\circ}F over 20 minutes. What is the AROC of the temperature?
NEED A HINT?
Think about the units. It should be 'degrees per minute'.
SHOW DETAILED EXPLANATION

Step 1: Change in Temp

ΔT=100180=80F\Delta T = 100 - 180 = -80^{\circ}F.

Step 2: AROC

8020=4F/min\frac{-80}{20} = -4^{\circ}F/min. The negative sign means it's cooling down.
Common Pitfalls
  • Mixing up the OrderIf you use f(b)f(a)f(b)-f(a) on top, you MUST use bab-a on the bottom. Swapping one but not the other flips the sign of your answer.

The 'Shrinking Interval' (Secant to Tangent)

This is the 'Big Bang' of Calculus. By moving the two points of a secant line closer and closer together, the gap between them eventually vanishes, leaving us with a line that touches the curve at exactly one point.

Core Theorem
The Tangent Intuition: As the interval width Δx0\Delta x \to 0, the Secant Line 'morphs' into the Tangent Line.
Step-by-Step SOP
  1. 1

    Pick a Pivot

    Choose the point where you want to find the 'instant' speed.
  2. 2

    Create a Sequence

    Calculate slopes over smaller and smaller intervals (0.1, 0.01, 0.001).

Practice Exercises


Example 01Medium
Given the table of slopes for f(x)f(x) starting at x=3x=3 with different interval widths hh:
-
h=0.1,m=6.1h=0.1, m=6.1
-
h=0.01,m=6.01h=0.01, m=6.01
-
h=0.001,m=6.001h=0.001, m=6.001
What is the estimated slope of the tangent line at
x=3x=3?
NEED A HINT?
Look at the number these slopes are 'chasing' as hh disappears.
SHOW DETAILED EXPLANATION

Analysis

As hh gets smaller, the slope values are clearly approaching the whole number 6.

Prediction

The Instantaneous Rate of Change at x=3x=3 is 6.
Common Pitfalls
  • The 0/0 ProblemIn algebra, dividing by zero is forbidden. In Calculus, we use 'Limits' to talk about getting infinitely close to zero without actually being zero.

Instantaneous Rate of Change (IROC) & Tangent Lines

IROC is the exact rate of change at a single moment in time. Geometrically, it is the slope of the Tangent Line.

Core Theorem
IROC = limh0f(a+h)f(a)h\lim_{h \to 0} \frac{f(a+h) - f(a)}{h}. (The formal derivative definition we'll see in Day 1).
Step-by-Step SOP
  1. 1

    The Surfer Test

    Imagine a surfer on the wave. The board represents the tangent line; its tilt is the IROC.
  2. 2

    Local Linearity

    Zoom in. If the curve looks like it's going up-right, the IROC is positive.

Practice Exercises


Example 01Hard
Rank the IROC (slopes) at points A, B, and C on a curve where A is a steep climb, B is the peak, and C is a gentle descent.
NEED A HINT?
Steep up = Large positive. Flat = Zero. Down = Negative.
SHOW DETAILED EXPLANATION

Visual Rank

Point A (Positive) > Point B (Zero) > Point C (Negative).
Example 02Medium
If a position graph is a straight line s(t)=5t+2s(t) = 5t + 2, what is the IROC at t=10t=10?
NEED A HINT?
Does the slope of a straight line ever change?
SHOW DETAILED EXPLANATION

Analysis

A straight line has a constant slope. Here, m=5m=5 everywhere.

Conclusion

The IROC is 5, regardless of the value of tt.
Common Pitfalls
  • Tangent vs. NormalRemember, the tangent line 'skims' the surface in the same direction as the curve. It doesn't cut through it perpendicularly.

Geometric Models & Similarity

Calculus often measures how physical quantities change. To do this, you must first have the 'container' formulas ready.

Core Theorem
Key Formulas:
1. Circle: Area
A=πr2A = \pi r^2, Circumference C=2πrC = 2\pi r.
2. Sphere: Volume
V=43πr3V = \frac{4}{3}\pi r^3, Surface Area S=4πr2S = 4\pi r^2.
3. Cone: Volume
V=13πr2hV = \frac{1}{3}\pi r^2 h.
4. Similarity: If two triangles are similar, the ratios of their corresponding sides are equal:
rh=RH\frac{r}{h} = \frac{R}{H}.
Step-by-Step SOP
  1. 1

    Dimension Reduction

    In multi-variable shapes (like cones), always use similarity or given constraints to reduce the formula to a single variable before differentiating.

Practice Exercises


Example 01Medium
A 1.8m tall man walks away from a 5m tall lamppost. If his distance from the post is xx and the length of his shadow is ss, express ss in terms of xx.
NEED A HINT?
Draw two right triangles: the small one (man + shadow) and the large one (lamppost + total distance).
SHOW DETAILED EXPLANATION

Step 1: Set up the Proportion

Using similar triangles: man’s heightshadow length=lamp heighttotal distance\frac{\text{man's height}}{\text{shadow length}} = \frac{\text{lamp height}}{\text{total distance}}.

Step 2: Plug in Variables

1.8s=5x+s\frac{1.8}{s} = \frac{5}{x + s}.

Step 3: Solve for s

1.8(x+s)=5s    1.8x+1.8s=5s    1.8x=3.2s    s=1.83.2x=916x1.8(x + s) = 5s \implies 1.8x + 1.8s = 5s \implies 1.8x = 3.2s \implies s = \frac{1.8}{3.2}x = \frac{9}{16}x.
Example 02Easy
The Melting Iceball: A spherical snowball is melting. If its surface area SS is currently 36π36\pi cm², find its volume VV.
NEED A HINT?
Use the surface area to find the radius rr first, then plug into the volume formula.
SHOW DETAILED EXPLANATION

Step 1: Find Radius

S=4πr2=36π    r2=9    r=3S = 4\pi r^2 = 36\pi \implies r^2 = 9 \implies r = 3 cm.

Step 2: Calculate Volume

V=43πr3=43π(3)3=43π(27)=36πV = \frac{4}{3}\pi r^3 = \frac{4}{3}\pi (3)^3 = \frac{4}{3}\pi (27) = 36\pi cm³.

Note

Interestingly, for a sphere with r=3r=3, the numerical values of SS and VV are the same (36π36\pi).
Example 03Hard
The Trough Problem: A water trough is 10m long and its ends are isosceles triangles with width 4m and height 3m. If the water level is hh, find the volume VV of water.
NEED A HINT?
Volume = (Area of triangular cross-section) ×\times length. Use similarity to find the water's width ww.
SHOW DETAILED EXPLANATION

Step 1: Find Water Width

By similar triangles on the end face: wh=43    w=43h\frac{w}{h} = \frac{4}{3} \implies w = \frac{4}{3}h.

Step 2: Area of Cross-section

Area =12wh=12(43h)h=23h2= \frac{1}{2} \cdot w \cdot h = \frac{1}{2} \cdot (\frac{4}{3}h) \cdot h = \frac{2}{3}h^2.

Step 3: Total Volume

V=Arealength=23h210=203h2V = \text{Area} \cdot \text{length} = \frac{2}{3}h^2 \cdot 10 = \frac{20}{3}h^2.

Absolute Values and Graph Transformations

To understand limits ($epsilon-delta$) and continuity, you must view functions not just as lines, but as distances and movements.

Core Theorem
1. Distance Interpretation: xa<L|x - a| < L means the distance between xx and aa is less than LL. (i.e., aL<x<a+La-L < x < a+L).
2. Transformations: For
y=af(b(xh))+ky = af(b(x-h)) + k:
-
h,kh, k: Horizontal/Vertical shift.
-
a,ba, b: Vertical/Horizontal stretch or compression.
3. Piecewise Splitting:
f(x)=f(x)|f(x)| = f(x) if f(x)0f(x) \geq 0, and f(x)-f(x) if f(x)<0f(x) < 0.
Step-by-Step SOP
  1. 1

    Breaking Absolute Values

    When dealing with g(x)|g(x)| in calculus, always split the domain based on the roots of g(x)g(x) to remove the bars.

Practice Exercises


Example 01Medium
Write f(x)=x3+2f(x) = |x - 3| + 2 as a piecewise function and describe its graph.
NEED A HINT?
Find the 'critical point' where the expression inside the absolute value is zero.
SHOW DETAILED EXPLANATION

Step 1: Case x < 3

x3x-3 is negative, so x3=(x3)|x-3| = -(x-3). f(x)=x+3+2=x+5f(x) = -x + 3 + 2 = -x + 5.

Step 2: Case x ≥ 3

x3x-3 is positive, so x3=x3|x-3| = x-3. f(x)=x3+2=x1f(x) = x - 3 + 2 = x - 1.

Step 3: Transformation View

This is the graph of y=xy = |x| shifted Right 3 units and Up 2 units. The 'corner' (non-differentiable point) is at (3,2)(3, 2).
Example 02Medium
Define f(x)=x2x2f(x) = \frac{|x-2|}{x-2} as a piecewise function. What happens at x=2x=2?
NEED A HINT?
Check the sign of (x2)(x-2) for values greater than and less than 2.
SHOW DETAILED EXPLANATION

Case x > 2

x2=x2|x-2| = x-2, so f(x)=x2x2=1f(x) = \frac{x-2}{x-2} = 1.

Case x < 2

x2=(x2)|x-2| = -(x-2), so f(x)=(x2)x2=1f(x) = \frac{-(x-2)}{x-2} = -1.

Conclusion

The function is 11 for x>2x>2 and 1-1 for x<2x<2. It is undefined at x=2x=2 (a jump discontinuity).
Example 03Easy
Solve the inequality 2x5<3|2x - 5| < 3 and interpret it as a distance.
NEED A HINT?
The distance between 2x2x and 55 is less than 3.
SHOW DETAILED EXPLANATION

Step 1: Split

3<2x5<3-3 < 2x - 5 < 3.

Step 2: Add 5

2<2x<82 < 2x < 8.

Step 3: Divide by 2

1<x<41 < x < 4.
Common Pitfalls
  • The Horizontal Stretch TrapIn f(bx)f(bx), if b=2b=2, the graph is compressed by half, NOT doubled. Inside moves are always counter-intuitive!